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104232421129 is a prime number
BaseRepresentation
bin110000100010010111…
…1001000011100001001
3100222001010200121112211
41201010233020130021
53201431444434004
6115514514305121
710346655650464
oct1410457103411
9328033617484
10104232421129
1140228536801
121824b2881a1
139aa162a445
14508b1d62db
152aa0ac0504
hex1844bc8709

104232421129 has 2 divisors, whose sum is σ = 104232421130. Its totient is φ = 104232421128.

The previous prime is 104232421127. The next prime is 104232421169. The reversal of 104232421129 is 921124232401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100329295504 + 3903125625 = 316748^2 + 62475^2 .

It is an emirp because it is prime and its reverse (921124232401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 104232421129 - 21 = 104232421127 is a prime.

It is a super-2 number, since 2×1042324211292 (a number of 23 digits) contains 22 as substring.

Together with 104232421127, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 104232421129.

It is not a weakly prime, because it can be changed into another prime (104232421127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52116210564 + 52116210565.

It is an arithmetic number, because the mean of its divisors is an integer number (52116210565).

Almost surely, 2104232421129 is an apocalyptic number.

It is an amenable number.

104232421129 is a deficient number, since it is larger than the sum of its proper divisors (1).

104232421129 is an equidigital number, since it uses as much as digits as its factorization.

104232421129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 104232421129 in words is "one hundred four billion, two hundred thirty-two million, four hundred twenty-one thousand, one hundred twenty-nine".