Base | Representation |
---|---|
bin | 10011011010100011… |
… | …10001110001001001 |
3 | 222220102022002020121 |
4 | 21231101301301021 |
5 | 132321331431213 |
6 | 4442143423241 |
7 | 516204454033 |
oct | 115521616111 |
9 | 28812262217 |
10 | 10423311433 |
11 | 4469762177 |
12 | 202a8b4b21 |
13 | ca1601502 |
14 | 70c474c53 |
15 | 41012888d |
hex | 26d471c49 |
10423311433 has 2 divisors, whose sum is σ = 10423311434. Its totient is φ = 10423311432.
The previous prime is 10423311407. The next prime is 10423311463. The reversal of 10423311433 is 33411332401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7532851264 + 2890460169 = 86792^2 + 53763^2 .
It is a cyclic number.
It is not a de Polignac number, because 10423311433 - 229 = 9886440521 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10423311398 and 10423311407.
It is not a weakly prime, because it can be changed into another prime (10423311463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211655716 + 5211655717.
It is an arithmetic number, because the mean of its divisors is an integer number (5211655717).
Almost surely, 210423311433 is an apocalyptic number.
It is an amenable number.
10423311433 is a deficient number, since it is larger than the sum of its proper divisors (1).
10423311433 is an equidigital number, since it uses as much as digits as its factorization.
10423311433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 10423311433 its reverse (33411332401), we get a palindrome (43834643834).
The spelling of 10423311433 in words is "ten billion, four hundred twenty-three million, three hundred eleven thousand, four hundred thirty-three".
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