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104247113 is a prime number
BaseRepresentation
bin1100011011010…
…10111101001001
321021011022011012
412031222331021
5203141401423
614202213305
72404041305
oct615527511
9237138135
10104247113
1153932443
122aab4235
131879c9a9
14dbb8d05
159243078
hex636af49

104247113 has 2 divisors, whose sum is σ = 104247114. Its totient is φ = 104247112.

The previous prime is 104247103. The next prime is 104247119. The reversal of 104247113 is 311742401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95199049 + 9048064 = 9757^2 + 3008^2 .

It is an emirp because it is prime and its reverse (311742401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 104247113 - 212 = 104243017 is a prime.

It is not a weakly prime, because it can be changed into another prime (104247119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52123556 + 52123557.

It is an arithmetic number, because the mean of its divisors is an integer number (52123557).

Almost surely, 2104247113 is an apocalyptic number.

It is an amenable number.

104247113 is a deficient number, since it is larger than the sum of its proper divisors (1).

104247113 is an equidigital number, since it uses as much as digits as its factorization.

104247113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 23.

The square root of 104247113 is about 10210.1475503540. The cubic root of 104247113 is about 470.6391079099.

Adding to 104247113 its reverse (311742401), we get a palindrome (415989514).

The spelling of 104247113 in words is "one hundred four million, two hundred forty-seven thousand, one hundred thirteen".