Base | Representation |
---|---|
bin | 1001011110111111001000… |
… | …1101000111110110100111 |
3 | 1100220220100201001201222001 |
4 | 2113233302031013312213 |
5 | 2331322414440404303 |
6 | 34102311140350131 |
7 | 2124252205211404 |
oct | 227576215076647 |
9 | 40826321051861 |
10 | 10427949153703 |
11 | 3360517494254 |
12 | 120500b0a5347 |
13 | 5a8474cc0c23 |
14 | 280a032072ab |
15 | 1313c53ac31d |
hex | 97bf2347da7 |
10427949153703 has 2 divisors, whose sum is σ = 10427949153704. Its totient is φ = 10427949153702.
The previous prime is 10427949153599. The next prime is 10427949153751. The reversal of 10427949153703 is 30735194972401.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10427949153703 is a prime.
It is a super-2 number, since 2×104279491537032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10427949163703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5213974576851 + 5213974576852.
It is an arithmetic number, because the mean of its divisors is an integer number (5213974576852).
Almost surely, 210427949153703 is an apocalyptic number.
10427949153703 is a deficient number, since it is larger than the sum of its proper divisors (1).
10427949153703 is an equidigital number, since it uses as much as digits as its factorization.
10427949153703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5715360, while the sum is 55.
The spelling of 10427949153703 in words is "ten trillion, four hundred twenty-seven billion, nine hundred forty-nine million, one hundred fifty-three thousand, seven hundred three".
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