104314132129451 has 2 divisors, whose sum is σ = 104314132129452. Its totient is φ = 104314132129450.

The previous prime is 104314132129397. The next prime is 104314132129453. The reversal of 104314132129451 is 154921231413401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 104314132129451 - 2³⁸ = 104039254222507 is a prime.

It is a super-3 number, since 3×104314132129451³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 104314132129453, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 104314132129399 and 104314132129408.

It is not a weakly prime, because it can be changed into another prime (104314132129453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52157066064725 + 52157066064726.

It is an arithmetic number, because the mean of its divisors is an integer number (52157066064726).

Almost surely, 2^{104314132129451} is an apocalyptic number.

104314132129451 is a deficient number, since it is larger than the sum of its proper divisors (1).

104314132129451 is an equidigital number, since it uses as much as digits as its factorization.

104314132129451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 41.

The spelling of 104314132129451 in words is "one hundred four trillion, three hundred fourteen billion, one hundred thirty-two million, one hundred twenty-nine thousand, four hundred fifty-one".