Base | Representation |
---|---|
bin | 110000100101000001… |
… | …0001110010110000011 |
3 | 100222021022221202002011 |
4 | 1201022002032112003 |
5 | 3202122223442011 |
6 | 115531411433351 |
7 | 10352115344101 |
oct | 1411202162603 |
9 | 328238852064 |
10 | 104321312131 |
11 | 4027372a943 |
12 | 18274bb5857 |
13 | 9ab6b8167a |
14 | 5098d34c71 |
15 | 2aa87cd621 |
hex | 184a08e583 |
104321312131 has 2 divisors, whose sum is σ = 104321312132. Its totient is φ = 104321312130.
The previous prime is 104321312111. The next prime is 104321312153. The reversal of 104321312131 is 131213123401.
It is an a-pointer prime, because the next prime (104321312153) can be obtained adding 104321312131 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104321312131 - 25 = 104321312099 is a prime.
It is a super-2 number, since 2×1043213121312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (104321312111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52160656065 + 52160656066.
It is an arithmetic number, because the mean of its divisors is an integer number (52160656066).
Almost surely, 2104321312131 is an apocalyptic number.
104321312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
104321312131 is an equidigital number, since it uses as much as digits as its factorization.
104321312131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 104321312131 its reverse (131213123401), we get a palindrome (235534435532).
The spelling of 104321312131 in words is "one hundred four billion, three hundred twenty-one million, three hundred twelve thousand, one hundred thirty-one".
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