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10433125341340 = 225134123319512153
BaseRepresentation
bin1001011111010010011010…
…1110101101100010011100
31100221101201102222022112021
42113310212232231202130
52331414020041410330
634104524524145524
72124524400115432
oct227644656554234
940841642868467
1010433125341340
11336273329a679
1212060146982a4
135a8abb4ba350
14280d7484cd52
151315c9a1767a
hex97d26bad89c

10433125341340 has 192 divisors, whose sum is σ = 24297857805312. Its totient is φ = 3738488832000.

The previous prime is 10433125341337. The next prime is 10433125341343. The reversal of 10433125341340 is 4314352133401.

It is an interprime number because it is at equal distance from previous prime (10433125341337) and next prime (10433125341343).

It is a super-2 number, since 2×104331253413402 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10433125341296 and 10433125341305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10433125341343) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4845853704 + ... + 4845855856.

It is an arithmetic number, because the mean of its divisors is an integer number (126551342736).

Almost surely, 210433125341340 is an apocalyptic number.

10433125341340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10433125341340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12148928902656).

10433125341340 is an abundant number, since it is smaller than the sum of its proper divisors (13864732463972).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10433125341340 is a wasteful number, since it uses less digits than its factorization.

10433125341340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4400 (or 4398 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 10433125341340 its reverse (4314352133401), we get a palindrome (14747477474741).

The spelling of 10433125341340 in words is "ten trillion, four hundred thirty-three billion, one hundred twenty-five million, three hundred forty-one thousand, three hundred forty".