Base | Representation |
---|---|
bin | 110000100101010100… |
… | …0100001010110001001 |
3 | 100222022000211210102011 |
4 | 1201022220201112021 |
5 | 3202132311221213 |
6 | 115532410535521 |
7 | 10352266566151 |
oct | 1411250412611 |
9 | 328260753364 |
10 | 104331351433 |
11 | 40279367591 |
12 | 182784375a1 |
13 | 9ab8c8809a |
14 | 509a3c9761 |
15 | 2aa961303d |
hex | 184aa21589 |
104331351433 has 2 divisors, whose sum is σ = 104331351434. Its totient is φ = 104331351432.
The previous prime is 104331351431. The next prime is 104331351437. The reversal of 104331351433 is 334153133401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 104052695184 + 278656249 = 322572^2 + 16693^2 .
It is a cyclic number.
It is not a de Polignac number, because 104331351433 - 21 = 104331351431 is a prime.
Together with 104331351431, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 104331351395 and 104331351404.
It is not a weakly prime, because it can be changed into another prime (104331351431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52165675716 + 52165675717.
It is an arithmetic number, because the mean of its divisors is an integer number (52165675717).
Almost surely, 2104331351433 is an apocalyptic number.
It is an amenable number.
104331351433 is a deficient number, since it is larger than the sum of its proper divisors (1).
104331351433 is an equidigital number, since it uses as much as digits as its factorization.
104331351433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 104331351433 its reverse (334153133401), we get a palindrome (438484484834).
The spelling of 104331351433 in words is "one hundred four billion, three hundred thirty-one million, three hundred fifty-one thousand, four hundred thirty-three".
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