Base | Representation |
---|---|
bin | 110000100101101001… |
… | …1001011011111100111 |
3 | 100222022210212221011201 |
4 | 1201023103023133213 |
5 | 3202143142042434 |
6 | 115533450343331 |
7 | 10352463622555 |
oct | 1411323133747 |
9 | 328283787151 |
10 | 104342534119 |
11 | 4028470527a |
12 | 1828012ab47 |
13 | 9abb3a2065 |
14 | 509ba9abd5 |
15 | 2aaa5c1614 |
hex | 184b4cb7e7 |
104342534119 has 2 divisors, whose sum is σ = 104342534120. Its totient is φ = 104342534118.
The previous prime is 104342534111. The next prime is 104342534171. The reversal of 104342534119 is 911435243401.
It is a weak prime.
It is an emirp because it is prime and its reverse (911435243401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 104342534119 - 23 = 104342534111 is a prime.
It is a super-2 number, since 2×1043425341192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104342534111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52171267059 + 52171267060.
It is an arithmetic number, because the mean of its divisors is an integer number (52171267060).
Almost surely, 2104342534119 is an apocalyptic number.
104342534119 is a deficient number, since it is larger than the sum of its proper divisors (1).
104342534119 is an equidigital number, since it uses as much as digits as its factorization.
104342534119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 104342534119 in words is "one hundred four billion, three hundred forty-two million, five hundred thirty-four thousand, one hundred nineteen".
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