Search a number
-
+
1043431101313 is a prime number
BaseRepresentation
bin11110010111100010101…
…01110001001110000001
310200202021111200222010221
433023301111301032001
5114043421330220223
62115202353423041
7135246124010446
oct17136125611601
93622244628127
101043431101313
11372575722157
1214a282b6aa81
137751a143263
14387065999cd
151c21e59ab5d
hexf2f1571381

1043431101313 has 2 divisors, whose sum is σ = 1043431101314. Its totient is φ = 1043431101312.

The previous prime is 1043431101301. The next prime is 1043431101409. The reversal of 1043431101313 is 3131011343401.

1043431101313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 967925404224 + 75505697089 = 983832^2 + 274783^2 .

It is a cyclic number.

It is not a de Polignac number, because 1043431101313 - 29 = 1043431100801 is a prime.

It is not a weakly prime, because it can be changed into another prime (1043431105313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521715550656 + 521715550657.

It is an arithmetic number, because the mean of its divisors is an integer number (521715550657).

Almost surely, 21043431101313 is an apocalyptic number.

It is an amenable number.

1043431101313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1043431101313 is an equidigital number, since it uses as much as digits as its factorization.

1043431101313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1043431101313 its reverse (3131011343401), we get a palindrome (4174442444714).

The spelling of 1043431101313 in words is "one trillion, forty-three billion, four hundred thirty-one million, one hundred one thousand, three hundred thirteen".