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1043881297049 is a prime number
BaseRepresentation
bin11110011000011000010…
…11001000010010011001
310200210102212211021121002
433030030023020102121
5114100332103001144
62115315154554345
7135263231423453
oct17141413102231
93623385737532
101043881297049
11372786861948
1214a3898989b5
137758c4ab076
143874a2a92d3
151c248d7714e
hexf30c2c8499

1043881297049 has 2 divisors, whose sum is σ = 1043881297050. Its totient is φ = 1043881297048.

The previous prime is 1043881296971. The next prime is 1043881297057. The reversal of 1043881297049 is 9407921883401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1039926773824 + 3954523225 = 1019768^2 + 62885^2 .

It is a cyclic number.

It is not a de Polignac number, because 1043881297049 - 236 = 975161820313 is a prime.

It is a super-2 number, since 2×10438812970492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1043881296985 and 1043881297003.

It is not a weakly prime, because it can be changed into another prime (1043881297079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521940648524 + 521940648525.

It is an arithmetic number, because the mean of its divisors is an integer number (521940648525).

Almost surely, 21043881297049 is an apocalyptic number.

It is an amenable number.

1043881297049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1043881297049 is an equidigital number, since it uses as much as digits as its factorization.

1043881297049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3483648, while the sum is 56.

The spelling of 1043881297049 in words is "one trillion, forty-three billion, eight hundred eighty-one million, two hundred ninety-seven thousand, forty-nine".