Base | Representation |
---|---|
bin | 110000100111111101… |
… | …1111011001100100011 |
3 | 100222112020021002000021 |
4 | 1201033323323030203 |
5 | 3202323100333011 |
6 | 115545305534311 |
7 | 10354430052604 |
oct | 1411773731443 |
9 | 328466232007 |
10 | 104420324131 |
11 | 40314607042 |
12 | 182a21a4397 |
13 | 9b0153a556 |
14 | 50a8149dab |
15 | 2ab233a471 |
hex | 184fefb323 |
104420324131 has 2 divisors, whose sum is σ = 104420324132. Its totient is φ = 104420324130.
The previous prime is 104420324117. The next prime is 104420324147. The reversal of 104420324131 is 131423024401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104420324131 - 29 = 104420323619 is a prime.
It is a super-3 number, since 3×1044203241313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 104420324096 and 104420324105.
It is not a weakly prime, because it can be changed into another prime (104420324101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52210162065 + 52210162066.
It is an arithmetic number, because the mean of its divisors is an integer number (52210162066).
Almost surely, 2104420324131 is an apocalyptic number.
104420324131 is a deficient number, since it is larger than the sum of its proper divisors (1).
104420324131 is an equidigital number, since it uses as much as digits as its factorization.
104420324131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 104420324131 its reverse (131423024401), we get a palindrome (235843348532).
The spelling of 104420324131 in words is "one hundred four billion, four hundred twenty million, three hundred twenty-four thousand, one hundred thirty-one".
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