Base | Representation |
---|---|
bin | 1001011111110111011010… |
… | …0010000010101110100011 |
3 | 1100222100100101202010222112 |
4 | 2113331312202002232203 |
5 | 2332044333324212011 |
6 | 34113250044425535 |
7 | 2125325421336365 |
oct | 227756642025643 |
9 | 40870311663875 |
10 | 10443054132131 |
11 | 33669688980a5 |
12 | 1207b258482ab |
13 | 5a9a1150479a |
14 | 281637356d35 |
15 | 1319ab50b58b |
hex | 97f76882ba3 |
10443054132131 has 2 divisors, whose sum is σ = 10443054132132. Its totient is φ = 10443054132130.
The previous prime is 10443054132083. The next prime is 10443054132139. The reversal of 10443054132131 is 13123145034401.
It is a strong prime.
It is an emirp because it is prime and its reverse (13123145034401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10443054132131 - 238 = 10168176225187 is a prime.
It is a super-2 number, since 2×104430541321312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10443054132139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5221527066065 + 5221527066066.
It is an arithmetic number, because the mean of its divisors is an integer number (5221527066066).
Almost surely, 210443054132131 is an apocalyptic number.
10443054132131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10443054132131 is an equidigital number, since it uses as much as digits as its factorization.
10443054132131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 10443054132131 its reverse (13123145034401), we get a palindrome (23566199166532).
The spelling of 10443054132131 in words is "ten trillion, four hundred forty-three billion, fifty-four million, one hundred thirty-two thousand, one hundred thirty-one".
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