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10443054132353 is a prime number
BaseRepresentation
bin1001011111110111011010…
…0010000010110010000001
31100222100100101202011021202
42113331312202002302001
52332044333324213403
634113250044430545
72125325421340133
oct227756642026201
940870311664252
1010443054132353
113366968898287
121207b25848455
135a9a1150490b
14281637357053
151319ab50b688
hex97f76882c81

10443054132353 has 2 divisors, whose sum is σ = 10443054132354. Its totient is φ = 10443054132352.

The previous prime is 10443054132331. The next prime is 10443054132373. The reversal of 10443054132353 is 35323145034401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10256954211904 + 186099920449 = 3202648^2 + 431393^2 .

It is a cyclic number.

It is not a de Polignac number, because 10443054132353 - 210 = 10443054131329 is a prime.

It is a super-3 number, since 3×104430541323533 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (10443054132373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5221527066176 + 5221527066177.

It is an arithmetic number, because the mean of its divisors is an integer number (5221527066177).

Almost surely, 210443054132353 is an apocalyptic number.

It is an amenable number.

10443054132353 is a deficient number, since it is larger than the sum of its proper divisors (1).

10443054132353 is an equidigital number, since it uses as much as digits as its factorization.

10443054132353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 10443054132353 its reverse (35323145034401), we get a palindrome (45766199166754).

The spelling of 10443054132353 in words is "ten trillion, four hundred forty-three billion, fifty-four million, one hundred thirty-two thousand, three hundred fifty-three".