10443113 has 2 divisors, whose sum is σ = 10443114. Its totient is φ = 10443112.

The previous prime is 10443107. The next prime is 10443119. The reversal of 10443113 is 31134401.

It is a balanced prime because it is at equal distance from previous prime (10443107) and next prime (10443119).

It can be written as a sum of positive squares in only one way, i.e., 10413529 + 29584 = 3227^2 + 172^2 .

It is an emirp because it is prime and its reverse (31134401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10443113 - 2¹⁸ = 10180969 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10443091 and 10443100.

It is not a weakly prime, because it can be changed into another prime (10443119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5221556 + 5221557.

It is an arithmetic number, because the mean of its divisors is an integer number (5221557).

Almost surely, 2^10443113 is an apocalyptic number.

It is an amenable number.

10443113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10443113 is an equidigital number, since it uses as much as digits as its factorization.

10443113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 10443113 is about 3231.5805730323. The cubic root of 10443113 is about 218.5797839923.

Adding to 10443113 its reverse (31134401), we get a palindrome (41577514).

The spelling of 10443113 in words is "ten million, four hundred forty-three thousand, one hundred thirteen".