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104433344131 is a prime number
BaseRepresentation
bin110000101000010110…
…1100101111010000011
3100222120010202120002111
41201100231211322003
53202334414003011
6115550453000151
710354645531024
oct1412055457203
9328503676074
10104433344131
114032099a176
12182a6623057
139b041488ac
1450a9b78c4b
152ab355d121
hex1850b65e83

104433344131 has 2 divisors, whose sum is σ = 104433344132. Its totient is φ = 104433344130.

The previous prime is 104433344083. The next prime is 104433344167. The reversal of 104433344131 is 131443334401.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-104433344131 is a prime.

It is a super-2 number, since 2×1044333441312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 104433344093 and 104433344102.

It is not a weakly prime, because it can be changed into another prime (104433342131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52216672065 + 52216672066.

It is an arithmetic number, because the mean of its divisors is an integer number (52216672066).

Almost surely, 2104433344131 is an apocalyptic number.

104433344131 is a deficient number, since it is larger than the sum of its proper divisors (1).

104433344131 is an equidigital number, since it uses as much as digits as its factorization.

104433344131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 104433344131 its reverse (131443334401), we get a palindrome (235876678532).

The spelling of 104433344131 in words is "one hundred four billion, four hundred thirty-three million, three hundred forty-four thousand, one hundred thirty-one".