Base | Representation |
---|---|
bin | 11110011010101101010… |
… | …10111100101010010001 |
3 | 10200220122222122111021211 |
4 | 33031112222330222101 |
5 | 114110412033331032 |
6 | 2120043203420121 |
7 | 135336216133501 |
oct | 17152652745221 |
9 | 3626588574254 |
10 | 1045131152017 |
11 | 37326831a437 |
12 | 14a678384641 |
13 | 7772b409914 |
14 | 38828295a01 |
15 | 1c2bd95e747 |
hex | f356abca91 |
1045131152017 has 2 divisors, whose sum is σ = 1045131152018. Its totient is φ = 1045131152016.
The previous prime is 1045131152011. The next prime is 1045131152111. The reversal of 1045131152017 is 7102511315401.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 641214976081 + 403916175936 = 800759^2 + 635544^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1045131152017 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1045131152017.
It is not a weakly prime, because it can be changed into another prime (1045131152011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 522565576008 + 522565576009.
It is an arithmetic number, because the mean of its divisors is an integer number (522565576009).
Almost surely, 21045131152017 is an apocalyptic number.
It is an amenable number.
1045131152017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1045131152017 is an equidigital number, since it uses as much as digits as its factorization.
1045131152017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 31.
Adding to 1045131152017 its reverse (7102511315401), we get a palindrome (8147642467418).
The spelling of 1045131152017 in words is "one trillion, forty-five billion, one hundred thirty-one million, one hundred fifty-two thousand, seventeen".
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