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104942544299 is a prime number
BaseRepresentation
bin110000110111100010…
…0000010010110101011
3101000212121220121101222
41201233010002112223
53204410242404144
6120113202532255
710403400623435
oct1415704022653
9330777817358
10104942544299
114056236a85a
121840906708b
139b857a2478
145117647655
152ae30e22ee
hex186f1025ab

104942544299 has 2 divisors, whose sum is σ = 104942544300. Its totient is φ = 104942544298.

The previous prime is 104942544283. The next prime is 104942544313. The reversal of 104942544299 is 992445249401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 104942544299 - 24 = 104942544283 is a prime.

It is a super-2 number, since 2×1049425442992 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 104942544299.

It is not a weakly prime, because it can be changed into another prime (104962544299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52471272149 + 52471272150.

It is an arithmetic number, because the mean of its divisors is an integer number (52471272150).

Almost surely, 2104942544299 is an apocalyptic number.

104942544299 is a deficient number, since it is larger than the sum of its proper divisors (1).

104942544299 is an equidigital number, since it uses as much as digits as its factorization.

104942544299 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3732480, while the sum is 53.

The spelling of 104942544299 in words is "one hundred four billion, nine hundred forty-two million, five hundred forty-four thousand, two hundred ninety-nine".