Base | Representation |
---|---|
bin | 1001100010110111001000… |
… | …1100100011110011110111 |
3 | 1101011021012012201212212211 |
4 | 2120231302030203303313 |
5 | 2333420234333433114 |
6 | 34153041050154251 |
7 | 2132130004442401 |
oct | 230556214436367 |
9 | 41137165655784 |
10 | 10494520999159 |
11 | 338677957004a |
12 | 1215aa9a22987 |
13 | 5b1824135762 |
14 | 283d1a803b71 |
15 | 132ebea536c4 |
hex | 98b72323cf7 |
10494520999159 has 2 divisors, whose sum is σ = 10494520999160. Its totient is φ = 10494520999158.
The previous prime is 10494520999153. The next prime is 10494520999189. The reversal of 10494520999159 is 95199902549401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10494520999159 - 217 = 10494520868087 is a prime.
It is a super-3 number, since 3×104945209991593 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 10494520999094 and 10494520999103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10494520999153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5247260499579 + 5247260499580.
It is an arithmetic number, because the mean of its divisors is an integer number (5247260499580).
Almost surely, 210494520999159 is an apocalyptic number.
10494520999159 is a deficient number, since it is larger than the sum of its proper divisors (1).
10494520999159 is an equidigital number, since it uses as much as digits as its factorization.
10494520999159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47239200, while the sum is 67.
The spelling of 10494520999159 in words is "ten trillion, four hundred ninety-four billion, five hundred twenty million, nine hundred ninety-nine thousand, one hundred fifty-nine".
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