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10494520999159 is a prime number
BaseRepresentation
bin1001100010110111001000…
…1100100011110011110111
31101011021012012201212212211
42120231302030203303313
52333420234333433114
634153041050154251
72132130004442401
oct230556214436367
941137165655784
1010494520999159
11338677957004a
121215aa9a22987
135b1824135762
14283d1a803b71
15132ebea536c4
hex98b72323cf7

10494520999159 has 2 divisors, whose sum is σ = 10494520999160. Its totient is φ = 10494520999158.

The previous prime is 10494520999153. The next prime is 10494520999189. The reversal of 10494520999159 is 95199902549401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10494520999159 - 217 = 10494520868087 is a prime.

It is a super-3 number, since 3×104945209991593 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 10494520999094 and 10494520999103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10494520999153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5247260499579 + 5247260499580.

It is an arithmetic number, because the mean of its divisors is an integer number (5247260499580).

Almost surely, 210494520999159 is an apocalyptic number.

10494520999159 is a deficient number, since it is larger than the sum of its proper divisors (1).

10494520999159 is an equidigital number, since it uses as much as digits as its factorization.

10494520999159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 47239200, while the sum is 67.

The spelling of 10494520999159 in words is "ten trillion, four hundred ninety-four billion, five hundred twenty million, nine hundred ninety-nine thousand, one hundred fifty-nine".