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1049501374193 is a prime number
BaseRepresentation
bin11110100010110110010…
…10000001011011110001
310201022221112222210002102
433101123022001123301
5114143334322433233
62122045000430145
7135552423330146
oct17213312013361
93638845883072
101049501374193
1137510018aaa8
1214b497a78355
1377c76944abc
1438b2085c3cd
151c4774651e8
hexf45b2816f1

1049501374193 has 2 divisors, whose sum is σ = 1049501374194. Its totient is φ = 1049501374192.

The previous prime is 1049501374183. The next prime is 1049501374199. The reversal of 1049501374193 is 3914731059401.

1049501374193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1000354031329 + 49147342864 = 1000177^2 + 221692^2 .

It is an emirp because it is prime and its reverse (3914731059401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1049501374193 - 24 = 1049501374177 is a prime.

It is a super-2 number, since 2×10495013741932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1049501374199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 524750687096 + 524750687097.

It is an arithmetic number, because the mean of its divisors is an integer number (524750687097).

Almost surely, 21049501374193 is an apocalyptic number.

It is an amenable number.

1049501374193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1049501374193 is an equidigital number, since it uses as much as digits as its factorization.

1049501374193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 408240, while the sum is 47.

The spelling of 1049501374193 in words is "one trillion, forty-nine billion, five hundred one million, three hundred seventy-four thousand, one hundred ninety-three".