Base | Representation |
---|---|
bin | 101000000011… |
… | …000001010101 |
3 | 201202100201202 |
4 | 220003001111 |
5 | 10141420013 |
6 | 1013002245 |
7 | 155142542 |
oct | 50030125 |
9 | 21670652 |
10 | 10498133 |
11 | 5a20448 |
12 | 3623385 |
13 | 2237519 |
14 | 1573bc9 |
15 | dc5858 |
hex | a03055 |
10498133 has 2 divisors, whose sum is σ = 10498134. Its totient is φ = 10498132.
The previous prime is 10498079. The next prime is 10498139. The reversal of 10498133 is 33189401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8254129 + 2244004 = 2873^2 + 1498^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10498133 is a prime.
It is a super-2 number, since 2×104981332 = 220421592971378, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 10498096 and 10498105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10498139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5249066 + 5249067.
It is an arithmetic number, because the mean of its divisors is an integer number (5249067).
Almost surely, 210498133 is an apocalyptic number.
It is an amenable number.
10498133 is a deficient number, since it is larger than the sum of its proper divisors (1).
10498133 is an equidigital number, since it uses as much as digits as its factorization.
10498133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
The square root of 10498133 is about 3240.0822520424. The cubic root of 10498133 is about 218.9629775549.
The spelling of 10498133 in words is "ten million, four hundred ninety-eight thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •