10500313012471 has 2 divisors, whose sum is σ = 10500313012472. Its totient is φ = 10500313012470.

The previous prime is 10500313012403. The next prime is 10500313012561. The reversal of 10500313012471 is 17421031300501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10500313012471 - 2¹⁵ = 10500312979703 is a prime.

It is a super-3 number, since 3×10500313012471³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10500313012771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5250156506235 + 5250156506236.

It is an arithmetic number, because the mean of its divisors is an integer number (5250156506236).

Almost surely, 2^{10500313012471} is an apocalyptic number.

10500313012471 is a deficient number, since it is larger than the sum of its proper divisors (1).

10500313012471 is an equidigital number, since it uses as much as digits as its factorization.

10500313012471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 10500313012471 its reverse (17421031300501), we get a palindrome (27921344312972).

The spelling of 10500313012471 in words is "ten trillion, five hundred billion, three hundred thirteen million, twelve thousand, four hundred seventy-one".