Search a number
-
+
1050055549981 is a prime number
BaseRepresentation
bin11110100011111000011…
…00000010010000011101
310201101101011202211100121
433101330030002100131
5114201003210044411
62122215554354541
7135602232623044
oct17217414022035
93641334684317
101050055549981
11375364a8a519
1214b61158ba51
13780346b7b79
1438b742b755b
151c4aae30571
hexf47c30241d

1050055549981 has 2 divisors, whose sum is σ = 1050055549982. Its totient is φ = 1050055549980.

The previous prime is 1050055549937. The next prime is 1050055550081. The reversal of 1050055549981 is 1899455500501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 726527797956 + 323527752025 = 852366^2 + 568795^2 .

It is a cyclic number.

It is not a de Polignac number, because 1050055549981 - 219 = 1050055025693 is a prime.

It is a super-2 number, since 2×10500555499812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1050055549901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525027774990 + 525027774991.

It is an arithmetic number, because the mean of its divisors is an integer number (525027774991).

Almost surely, 21050055549981 is an apocalyptic number.

It is an amenable number.

1050055549981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1050055549981 is an equidigital number, since it uses as much as digits as its factorization.

1050055549981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620000, while the sum is 52.

The spelling of 1050055549981 in words is "one trillion, fifty billion, fifty-five million, five hundred forty-nine thousand, nine hundred eighty-one".