Search a number
-
+
105006010433 is a prime number
BaseRepresentation
bin110000111001011011…
…0001001000001000001
3101001001001100000120112
41201302312021001001
53210023014313213
6120123351121105
710405101235052
oct1416266110101
9331031300515
10105006010433
1140595178905
1218426373195
139b95993cac
145121c48729
152ae897bea8
hex1872d89041

105006010433 has 2 divisors, whose sum is σ = 105006010434. Its totient is φ = 105006010432.

The previous prime is 105006010423. The next prime is 105006010511. The reversal of 105006010433 is 334010600501.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 67025067664 + 37980942769 = 258892^2 + 194887^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-105006010433 is a prime.

It is a super-2 number, since 2×1050060104332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105006010399 and 105006010408.

It is not a weakly prime, because it can be changed into another prime (105006010423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52503005216 + 52503005217.

It is an arithmetic number, because the mean of its divisors is an integer number (52503005217).

Almost surely, 2105006010433 is an apocalyptic number.

It is an amenable number.

105006010433 is a deficient number, since it is larger than the sum of its proper divisors (1).

105006010433 is an equidigital number, since it uses as much as digits as its factorization.

105006010433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 105006010433 its reverse (334010600501), we get a palindrome (439016610934).

The spelling of 105006010433 in words is "one hundred five billion, six million, ten thousand, four hundred thirty-three".