Base | Representation |
---|---|
bin | 10011100011110101… |
… | …01110100011000101 |
3 | 1000002211202221120011 |
4 | 21301322232203011 |
5 | 133001243430023 |
6 | 4454004110221 |
7 | 521141226166 |
oct | 116172564305 |
9 | 30084687504 |
10 | 10501155013 |
11 | 44a96a0208 |
12 | 2050995371 |
13 | cb47881bb |
14 | 71893976d |
15 | 416da350d |
hex | 271eae8c5 |
10501155013 has 2 divisors, whose sum is σ = 10501155014. Its totient is φ = 10501155012.
The previous prime is 10501154999. The next prime is 10501155029. The reversal of 10501155013 is 31055110501.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10016406724 + 484748289 = 100082^2 + 22017^2 .
It is an emirp because it is prime and its reverse (31055110501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10501155013 - 29 = 10501154501 is a prime.
It is a super-2 number, since 2×105011550132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10501155043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5250577506 + 5250577507.
It is an arithmetic number, because the mean of its divisors is an integer number (5250577507).
Almost surely, 210501155013 is an apocalyptic number.
It is an amenable number.
10501155013 is a deficient number, since it is larger than the sum of its proper divisors (1).
10501155013 is an equidigital number, since it uses as much as digits as its factorization.
10501155013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 375, while the sum is 22.
Adding to 10501155013 its reverse (31055110501), we get a palindrome (41556265514).
The spelling of 10501155013 in words is "ten billion, five hundred one million, one hundred fifty-five thousand, thirteen".
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