1050121251331 has 2 divisors, whose sum is σ = 1050121251332. Its totient is φ = 1050121251330.

The previous prime is 1050121251301. The next prime is 1050121251337. The reversal of 1050121251331 is 1331521210501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1050121251331 - 2²¹ = 1050119154179 is a prime.

It is a super-2 number, since 2×1050121251331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1050121251296 and 1050121251305.

It is not a weakly prime, because it can be changed into another prime (1050121251337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525060625665 + 525060625666.

It is an arithmetic number, because the mean of its divisors is an integer number (525060625666).

Almost surely, 2^{1050121251331} is an apocalyptic number.

1050121251331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1050121251331 is an equidigital number, since it uses as much as digits as its factorization.

1050121251331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 1050121251331 its reverse (1331521210501), we get a palindrome (2381642461832).

The spelling of 1050121251331 in words is "one trillion, fifty billion, one hundred twenty-one million, two hundred fifty-one thousand, three hundred thirty-one".