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10501664713 is a prime number
BaseRepresentation
bin10011100011111001…
…01010111111001001
31000002212201211201221
421301330222333021
5133001411232323
64454023042041
7521145451201
oct116174527711
930085654657
1010501664713
1144a9a09151
122050ba0321
13cb49061b7
14718a2d401
15416e5455d
hex271f2afc9

10501664713 has 2 divisors, whose sum is σ = 10501664714. Its totient is φ = 10501664712.

The previous prime is 10501664659. The next prime is 10501664717. The reversal of 10501664713 is 31746610501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7075669689 + 3425995024 = 84117^2 + 58532^2 .

It is an emirp because it is prime and its reverse (31746610501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10501664713 is a prime.

It is a super-2 number, since 2×105016647132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10501664717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5250832356 + 5250832357.

It is an arithmetic number, because the mean of its divisors is an integer number (5250832357).

Almost surely, 210501664713 is an apocalyptic number.

It is an amenable number.

10501664713 is a deficient number, since it is larger than the sum of its proper divisors (1).

10501664713 is an equidigital number, since it uses as much as digits as its factorization.

10501664713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 34.

The spelling of 10501664713 in words is "ten billion, five hundred one million, six hundred sixty-four thousand, seven hundred thirteen".