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105031437050 = 2522100628741
BaseRepresentation
bin110000111010001011…
…1001000101011111010
3101001002211011211100002
41201310113020223322
53210101021441200
6120130100113002
710405530325121
oct1416427105372
9331084154302
10105031437050
11405a8565241
1218432995762
139b9b027427
145125386ab8
152aead00bd5
hex18745c8afa

105031437050 has 12 divisors (see below), whose sum is σ = 195358473006. Its totient is φ = 42012574800.

The previous prime is 105031437029. The next prime is 105031437061. The reversal of 105031437050 is 50734130501.

It can be written as a sum of positive squares in 3 ways, for example, as 44501168209 + 60530268841 = 210953^2 + 246029^2 .

It is a super-2 number, since 2×1050314370502 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1050314321 + ... + 1050314420.

Almost surely, 2105031437050 is an apocalyptic number.

105031437050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

105031437050 is a deficient number, since it is larger than the sum of its proper divisors (90327035956).

105031437050 is a wasteful number, since it uses less digits than its factorization.

105031437050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2100628753 (or 2100628748 counting only the distinct ones).

The product of its (nonzero) digits is 6300, while the sum is 29.

Adding to 105031437050 its reverse (50734130501), we get a palindrome (155765567551).

The spelling of 105031437050 in words is "one hundred five billion, thirty-one million, four hundred thirty-seven thousand, fifty".

Divisors: 1 2 5 10 25 50 2100628741 4201257482 10503143705 21006287410 52515718525 105031437050