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1050325147 is a prime number
BaseRepresentation
bin111110100110101…
…011000010011011
32201012101001020101
4332212223002123
54122340401042
6252120040231
735012421304
oct7646530233
92635331211
101050325147
11499976913
12253903077
131397aa591
149d6cb7ab
15623226b7
hex3e9ab09b

1050325147 has 2 divisors, whose sum is σ = 1050325148. Its totient is φ = 1050325146.

The previous prime is 1050325123. The next prime is 1050325163. The reversal of 1050325147 is 7415230501.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1050325147 is a prime.

It is a super-2 number, since 2×10503251472 = 2206365828841143218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1050325117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525162573 + 525162574.

It is an arithmetic number, because the mean of its divisors is an integer number (525162574).

Almost surely, 21050325147 is an apocalyptic number.

1050325147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1050325147 is an equidigital number, since it uses as much as digits as its factorization.

1050325147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4200, while the sum is 28.

The square root of 1050325147 is about 32408.7202308268. The cubic root of 1050325147 is about 1016.5012597100.

Adding to 1050325147 its reverse (7415230501), we get a palindrome (8465555648).

The spelling of 1050325147 in words is "one billion, fifty million, three hundred twenty-five thousand, one hundred forty-seven".