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105035257266113 is a prime number
BaseRepresentation
bin10111111000011101101101…
…001100101011111111000001
3111202220021100200012100101202
4113320131231030223333001
5102231344201330003423
61011220310412510545
731060355406544616
oct2770355514537701
9452807320170352
10105035257266113
1130516225510599
12b94465317b455
13467ba22818945
141bd1a3ad1250d
15c2231c43d728
hex5f876d32bfc1

105035257266113 has 2 divisors, whose sum is σ = 105035257266114. Its totient is φ = 105035257266112.

The previous prime is 105035257266013. The next prime is 105035257266131. The reversal of 105035257266113 is 311662752530501.

Together with next prime (105035257266131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73732653379984 + 31302603886129 = 8586772^2 + 5594873^2 .

It is a cyclic number.

It is not a de Polignac number, because 105035257266113 - 28 = 105035257265857 is a prime.

It is a super-2 number, since 2×1050352572661132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105035257266013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52517628633056 + 52517628633057.

It is an arithmetic number, because the mean of its divisors is an integer number (52517628633057).

Almost surely, 2105035257266113 is an apocalyptic number.

It is an amenable number.

105035257266113 is a deficient number, since it is larger than the sum of its proper divisors (1).

105035257266113 is an equidigital number, since it uses as much as digits as its factorization.

105035257266113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134000, while the sum is 47.

The spelling of 105035257266113 in words is "one hundred five trillion, thirty-five billion, two hundred fifty-seven million, two hundred sixty-six thousand, one hundred thirteen".