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105041491 is a prime number
BaseRepresentation
bin1100100001011…
…00111001010011
321022122122211121
412100230321103
5203342311431
614231223111
72413560262
oct620547123
9238578747
10105041491
1154325255
122b217a97
13189ba439
14dd445d9
15934d611
hex642ce53

105041491 has 2 divisors, whose sum is σ = 105041492. Its totient is φ = 105041490.

The previous prime is 105041479. The next prime is 105041527. The reversal of 105041491 is 194140501.

It is a weak prime.

It is an emirp because it is prime and its reverse (194140501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 105041491 - 211 = 105039443 is a prime.

It is a super-2 number, since 2×1050414912 = 22067429663006162, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105041441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52520745 + 52520746.

It is an arithmetic number, because the mean of its divisors is an integer number (52520746).

Almost surely, 2105041491 is an apocalyptic number.

105041491 is a deficient number, since it is larger than the sum of its proper divisors (1).

105041491 is an equidigital number, since it uses as much as digits as its factorization.

105041491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

The square root of 105041491 is about 10248.9751194937. The cubic root of 105041491 is about 471.8315301155.

Adding to 105041491 its reverse (194140501), we get a palindrome (299181992).

The spelling of 105041491 in words is "one hundred five million, forty-one thousand, four hundred ninety-one".