Search a number
-
+
105050066549873 is a prime number
BaseRepresentation
bin10111111000101011011111…
…111001100111110001110001
3111202221200120202110220120212
4113320223133321213301301
5102232120014014043443
61011231200115113505
731061421402434204
oct2770533771476161
9452850522426525
10105050066549873
1130521534a10685
12b9474a68a2895
1346802429ab243
141bd2643a8d93b
15c228d762e618
hex5f8adfe67c71

105050066549873 has 2 divisors, whose sum is σ = 105050066549874. Its totient is φ = 105050066549872.

The previous prime is 105050066549863. The next prime is 105050066550047. The reversal of 105050066549873 is 378945660050501.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104603638118464 + 446428431409 = 10227592^2 + 668153^2 .

It is an emirp because it is prime and its reverse (378945660050501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 105050066549873 - 26 = 105050066549809 is a prime.

It is a super-2 number, since 2×1050500665498732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105050066549863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52525033274936 + 52525033274937.

It is an arithmetic number, because the mean of its divisors is an integer number (52525033274937).

Almost surely, 2105050066549873 is an apocalyptic number.

It is an amenable number.

105050066549873 is a deficient number, since it is larger than the sum of its proper divisors (1).

105050066549873 is an equidigital number, since it uses as much as digits as its factorization.

105050066549873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216000, while the sum is 59.

The spelling of 105050066549873 in words is "one hundred five trillion, fifty billion, sixty-six million, five hundred forty-nine thousand, eight hundred seventy-three".