Base | Representation |
---|---|
bin | 10011100100101100… |
… | …11100010001001101 |
3 | 1000010100110001111011 |
4 | 21302112130101031 |
5 | 133010123421143 |
6 | 4454423525221 |
7 | 521260045336 |
oct | 116226342115 |
9 | 30110401434 |
10 | 10508420173 |
11 | 4502802679 |
12 | 20532b9811 |
13 | cb6130004 |
14 | 7198ab28d |
15 | 41783ae9d |
hex | 27259c44d |
10508420173 has 2 divisors, whose sum is σ = 10508420174. Its totient is φ = 10508420172.
The previous prime is 10508420147. The next prime is 10508420179. The reversal of 10508420173 is 37102480501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10502765289 + 5654884 = 102483^2 + 2378^2 .
It is a cyclic number.
It is not a de Polignac number, because 10508420173 - 25 = 10508420141 is a prime.
It is a super-3 number, since 3×105084201733 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10508420179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5254210086 + 5254210087.
It is an arithmetic number, because the mean of its divisors is an integer number (5254210087).
Almost surely, 210508420173 is an apocalyptic number.
It is an amenable number.
10508420173 is a deficient number, since it is larger than the sum of its proper divisors (1).
10508420173 is an equidigital number, since it uses as much as digits as its factorization.
10508420173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
The spelling of 10508420173 in words is "ten billion, five hundred eight million, four hundred twenty thousand, one hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.119 sec. • engine limits •