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10511000041 is a prime number
BaseRepresentation
bin10011100101000000…
…10010000111101001
31000010112022010101211
421302200102013221
5133011304000131
64454555113121
7521321011663
oct116240220751
930115263354
1010511000041
1145042049a3
1220541427a1
13cb6824369
14719d7d533
15417b9a5b1
hex2728121e9

10511000041 has 2 divisors, whose sum is σ = 10511000042. Its totient is φ = 10511000040.

The previous prime is 10511000039. The next prime is 10511000063. The reversal of 10511000041 is 14000011501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6022536025 + 4488464016 = 77605^2 + 66996^2 .

It is a cyclic number.

It is not a de Polignac number, because 10511000041 - 21 = 10511000039 is a prime.

It is a super-2 number, since 2×105110000412 (a number of 21 digits) contains 22 as substring.

Together with 10511000039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10510999985 and 10511000030.

It is not a weakly prime, because it can be changed into another prime (10511000011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5255500020 + 5255500021.

It is an arithmetic number, because the mean of its divisors is an integer number (5255500021).

Almost surely, 210511000041 is an apocalyptic number.

It is an amenable number.

10511000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

10511000041 is an equidigital number, since it uses as much as digits as its factorization.

10511000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20, while the sum is 13.

Adding to 10511000041 its reverse (14000011501), we get a palindrome (24511011542).

The spelling of 10511000041 in words is "ten billion, five hundred eleven million, forty-one", and thus it is an aban number.