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105113117 is a prime number
BaseRepresentation
bin1100100001111…
…10011000011101
321022210022002102
412100332120131
5203402104432
614232534445
72414306144
oct620763035
9238708072
10105113117
115437404a
122b251425
1318a13c15
14dd6275b
159364962
hex643e61d

105113117 has 2 divisors, whose sum is σ = 105113118. Its totient is φ = 105113116.

The previous prime is 105113101. The next prime is 105113167. The reversal of 105113117 is 711311501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71808676 + 33304441 = 8474^2 + 5771^2 .

It is a cyclic number.

It is not a de Polignac number, because 105113117 - 24 = 105113101 is a prime.

It is a super-2 number, since 2×1051131172 = 22097534730911378, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105113167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52556558 + 52556559.

It is an arithmetic number, because the mean of its divisors is an integer number (52556559).

Almost surely, 2105113117 is an apocalyptic number.

It is an amenable number.

105113117 is a deficient number, since it is larger than the sum of its proper divisors (1).

105113117 is an equidigital number, since it uses as much as digits as its factorization.

105113117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 105, while the sum is 20.

The square root of 105113117 is about 10252.4688246295. The cubic root of 105113117 is about 471.9387503712.

Adding to 105113117 its reverse (711311501), we get a palindrome (816424618).

The spelling of 105113117 in words is "one hundred five million, one hundred thirteen thousand, one hundred seventeen".