Base | Representation |
---|---|
bin | 110000111100110100… |
… | …0111111100000001111 |
3 | 101001022222211111111121 |
4 | 1201321220333200033 |
5 | 3210241210112421 |
6 | 120142542301411 |
7 | 10410654202123 |
oct | 1417150774017 |
9 | 331288744447 |
10 | 105120004111 |
11 | 40643557a61 |
12 | 18458587867 |
13 | 9bb3497085 |
14 | 513303d583 |
15 | 2b03997d41 |
hex | 1879a3f80f |
105120004111 has 2 divisors, whose sum is σ = 105120004112. Its totient is φ = 105120004110.
The previous prime is 105120004039. The next prime is 105120004123. The reversal of 105120004111 is 111400021501.
It is a strong prime.
It is an emirp because it is prime and its reverse (111400021501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 105120004111 - 223 = 105111615503 is a prime.
It is a super-2 number, since 2×1051200041112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105120004211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52560002055 + 52560002056.
It is an arithmetic number, because the mean of its divisors is an integer number (52560002056).
Almost surely, 2105120004111 is an apocalyptic number.
105120004111 is a deficient number, since it is larger than the sum of its proper divisors (1).
105120004111 is an equidigital number, since it uses as much as digits as its factorization.
105120004111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 105120004111 its reverse (111400021501), we get a palindrome (216520025612).
The spelling of 105120004111 in words is "one hundred five billion, one hundred twenty million, four thousand, one hundred eleven".
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