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105121317143371 is a prime number
BaseRepresentation
bin10111111001101101110110…
…110001000100001101001011
3111210012111111100001002020011
4113321231312301010031023
5102234301424142041441
61011324022202412351
731066523143461064
oct2771556661041513
9453174440032204
10105121317143371
11305497780250a1
12b9592705010b7
134686b89252639
141bd5c8280556b
15c246a7921581
hex5f9b76c4434b

105121317143371 has 2 divisors, whose sum is σ = 105121317143372. Its totient is φ = 105121317143370.

The previous prime is 105121317143363. The next prime is 105121317143431. The reversal of 105121317143371 is 173341713121501.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 105121317143371 - 23 = 105121317143363 is a prime.

It is a super-2 number, since 2×1051213171433712 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105121317143321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52560658571685 + 52560658571686.

It is an arithmetic number, because the mean of its divisors is an integer number (52560658571686).

Almost surely, 2105121317143371 is an apocalyptic number.

105121317143371 is a deficient number, since it is larger than the sum of its proper divisors (1).

105121317143371 is an equidigital number, since it uses as much as digits as its factorization.

105121317143371 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52920, while the sum is 40.

The spelling of 105121317143371 in words is "one hundred five trillion, one hundred twenty-one billion, three hundred seventeen million, one hundred forty-three thousand, three hundred seventy-one".