Base | Representation |
---|---|
bin | 110000111100111001… |
… | …1001000011101010111 |
3 | 101001100011211112202111 |
4 | 1201321303020131113 |
5 | 3210242400142411 |
6 | 120143115251451 |
7 | 10411015612546 |
oct | 1417163103527 |
9 | 331304745674 |
10 | 105122662231 |
11 | 40645003054 |
12 | 18459449b87 |
13 | 9bb3bb7c22 |
14 | 513353215d |
15 | 2b03d20721 |
hex | 1879cc8757 |
105122662231 has 2 divisors, whose sum is σ = 105122662232. Its totient is φ = 105122662230.
The previous prime is 105122662081. The next prime is 105122662241. The reversal of 105122662231 is 132266221501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 105122662231 - 215 = 105122629463 is a prime.
It is a super-2 number, since 2×1051226622312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 105122662193 and 105122662202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105122662241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52561331115 + 52561331116.
It is an arithmetic number, because the mean of its divisors is an integer number (52561331116).
Almost surely, 2105122662231 is an apocalyptic number.
105122662231 is a deficient number, since it is larger than the sum of its proper divisors (1).
105122662231 is an equidigital number, since it uses as much as digits as its factorization.
105122662231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 105122662231 its reverse (132266221501), we get a palindrome (237388883732).
The spelling of 105122662231 in words is "one hundred five billion, one hundred twenty-two million, six hundred sixty-two thousand, two hundred thirty-one".
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