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10514031433 is a prime number
BaseRepresentation
bin10011100101010111…
…10110001101001001
31000010202000010200121
421302223312031021
5133013043001213
64455144103241
7521355535603
oct116253661511
930122003617
1010514031433
114505995484
122055164b21
13cb7346099
1471a52c173
1541809888d
hex272af6349

10514031433 has 2 divisors, whose sum is σ = 10514031434. Its totient is φ = 10514031432.

The previous prime is 10514031383. The next prime is 10514031449. The reversal of 10514031433 is 33413041501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6205027984 + 4309003449 = 78772^2 + 65643^2 .

It is a cyclic number.

It is not a de Polignac number, because 10514031433 - 225 = 10480477001 is a prime.

It is a super-2 number, since 2×105140314332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10514031398 and 10514031407.

It is not a weakly prime, because it can be changed into another prime (10514031133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5257015716 + 5257015717.

It is an arithmetic number, because the mean of its divisors is an integer number (5257015717).

Almost surely, 210514031433 is an apocalyptic number.

It is an amenable number.

10514031433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10514031433 is an equidigital number, since it uses as much as digits as its factorization.

10514031433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 10514031433 its reverse (33413041501), we get a palindrome (43927072934).

The spelling of 10514031433 in words is "ten billion, five hundred fourteen million, thirty-one thousand, four hundred thirty-three".