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1051963385113 is a prime number
BaseRepresentation
bin11110100111011011110…
…01110110010100011001
310201120022010200220011001
433103231321312110121
5114213410111310423
62123133150105001
7136000430144434
oct17235571662431
93646263626131
101051963385113
113761539a7273
1214ba644ab161
1378279a32ab4
1438cb582081b
151c56d689cad
hexf4ede76519

1051963385113 has 2 divisors, whose sum is σ = 1051963385114. Its totient is φ = 1051963385112.

The previous prime is 1051963385071. The next prime is 1051963385141. The reversal of 1051963385113 is 3115833691501.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1019689981209 + 32273403904 = 1009797^2 + 179648^2 .

It is an emirp because it is prime and its reverse (3115833691501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1051963385113 is a prime.

It is a super-2 number, since 2×10519633851132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1051963385173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525981692556 + 525981692557.

It is an arithmetic number, because the mean of its divisors is an integer number (525981692557).

Almost surely, 21051963385113 is an apocalyptic number.

It is an amenable number.

1051963385113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051963385113 is an equidigital number, since it uses as much as digits as its factorization.

1051963385113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 46.

The spelling of 1051963385113 in words is "one trillion, fifty-one billion, nine hundred sixty-three million, three hundred eighty-five thousand, one hundred thirteen".