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105203051 is a prime number
BaseRepresentation
bin1100100010101…
…00010101101011
321022221212110022
412101110111223
5203412444201
614234511055
72415132302
oct621242553
9238855408
10105203051
1154425678
122b29548b
1318a45b35
14dd87439
15938141b
hex645456b

105203051 has 2 divisors, whose sum is σ = 105203052. Its totient is φ = 105203050.

The previous prime is 105203041. The next prime is 105203053. The reversal of 105203051 is 150302501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 105203051 - 218 = 104940907 is a prime.

It is a super-2 number, since 2×1052030512 = 22135363879417202, which contains 22 as substring.

Together with 105203053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (105203053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52601525 + 52601526.

It is an arithmetic number, because the mean of its divisors is an integer number (52601526).

Almost surely, 2105203051 is an apocalyptic number.

105203051 is a deficient number, since it is larger than the sum of its proper divisors (1).

105203051 is an equidigital number, since it uses as much as digits as its factorization.

105203051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 105203051 is about 10256.8538548621. The cubic root of 105203051 is about 472.0733077629.

Adding to 105203051 its reverse (150302501), we get a palindrome (255505552).

The spelling of 105203051 in words is "one hundred five million, two hundred three thousand, fifty-one".