10520431115147 has 2 divisors, whose sum is σ = 10520431115148. Its totient is φ = 10520431115146.

The previous prime is 10520431115113. The next prime is 10520431115149. The reversal of 10520431115147 is 74151113402501.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10520431115147 is a prime.

It is a super-2 number, since 2×10520431115147² (a number of 27 digits) contains 22 as substring.

Together with 10520431115149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10520431115149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5260215557573 + 5260215557574.

It is an arithmetic number, because the mean of its divisors is an integer number (5260215557574).

Almost surely, 2^{10520431115147} is an apocalyptic number.

10520431115147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10520431115147 is an equidigital number, since it uses as much as digits as its factorization.

10520431115147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 35.

Adding to 10520431115147 its reverse (74151113402501), we get a palindrome (84671544517648).

The spelling of 10520431115147 in words is "ten trillion, five hundred twenty billion, four hundred thirty-one million, one hundred fifteen thousand, one hundred forty-seven".