Base | Representation |
---|---|
bin | 1001100100011000000100… |
… | …1100010110001100001111 |
3 | 1101020202100200121021122012 |
4 | 2121012001030112030033 |
5 | 2334332032323433031 |
6 | 34213023115211435 |
7 | 2134040563651454 |
oct | 231060114261417 |
9 | 41222320537565 |
10 | 10520542405391 |
11 | 3396811a10757 |
12 | 121ab50446b7b |
13 | 5b4110162655 |
14 | 2852a86ab82b |
15 | 1339e4234b2b |
hex | 9918131630f |
10520542405391 has 2 divisors, whose sum is σ = 10520542405392. Its totient is φ = 10520542405390.
The previous prime is 10520542405379. The next prime is 10520542405463. The reversal of 10520542405391 is 19350424502501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10520542405391 - 230 = 10519468663567 is a prime.
It is a super-2 number, since 2×105205424053912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10520542405091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5260271202695 + 5260271202696.
It is an arithmetic number, because the mean of its divisors is an integer number (5260271202696).
Almost surely, 210520542405391 is an apocalyptic number.
10520542405391 is a deficient number, since it is larger than the sum of its proper divisors (1).
10520542405391 is an equidigital number, since it uses as much as digits as its factorization.
10520542405391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 41.
Adding to 10520542405391 its reverse (19350424502501), we get a palindrome (29870966907892).
The spelling of 10520542405391 in words is "ten trillion, five hundred twenty billion, five hundred forty-two million, four hundred five thousand, three hundred ninety-one".
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