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10521214051 is a prime number
BaseRepresentation
bin10011100110001110…
…01111110001100011
31000011020112001101111
421303013033301203
5133021412322201
64500002044151
7521503562305
oct116307176143
930136461344
1010521214051
114509a50927
122057649657
13cb898c45a
1471b47b975
15418a16b51
hex2731cfc63

10521214051 has 2 divisors, whose sum is σ = 10521214052. Its totient is φ = 10521214050.

The previous prime is 10521214049. The next prime is 10521214061. The reversal of 10521214051 is 15041212501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10521214051 - 21 = 10521214049 is a prime.

It is a super-2 number, since 2×105212140512 (a number of 21 digits) contains 22 as substring.

Together with 10521214049, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (10521214061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5260607025 + 5260607026.

It is an arithmetic number, because the mean of its divisors is an integer number (5260607026).

Almost surely, 210521214051 is an apocalyptic number.

10521214051 is a deficient number, since it is larger than the sum of its proper divisors (1).

10521214051 is an equidigital number, since it uses as much as digits as its factorization.

10521214051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 400, while the sum is 22.

Adding to 10521214051 its reverse (15041212501), we get a palindrome (25562426552).

The spelling of 10521214051 in words is "ten billion, five hundred twenty-one million, two hundred fourteen thousand, fifty-one".