Base | Representation |
---|---|
bin | 1001100100111111011101… |
… | …1000011001110100010111 |
3 | 1101021202122112012111210012 |
4 | 2121033313120121310113 |
5 | 2340020210443241210 |
6 | 34221532203150435 |
7 | 2134563565223624 |
oct | 231176730316427 |
9 | 41252575174705 |
10 | 10531115212055 |
11 | 33a0247a9a8a9 |
12 | 122100121541b |
13 | 5b5106717079 |
14 | 2859cc93934b |
15 | 133e1253d305 |
hex | 993f7619d17 |
10531115212055 has 32 divisors (see below), whose sum is σ = 13449452544000. Its totient is φ = 7888583526912.
The previous prime is 10531115212039. The next prime is 10531115212141. The reversal of 10531115212055 is 55021251113501.
It is a cyclic number.
It is not a de Polignac number, because 10531115212055 - 24 = 10531115212039 is a prime.
It is a super-2 number, since 2×105311152120552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 178576004 + ... + 178634966.
It is an arithmetic number, because the mean of its divisors is an integer number (420295392000).
Almost surely, 210531115212055 is an apocalyptic number.
10531115212055 is a deficient number, since it is larger than the sum of its proper divisors (2918337331945).
10531115212055 is a wasteful number, since it uses less digits than its factorization.
10531115212055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69743.
The product of its (nonzero) digits is 7500, while the sum is 32.
Adding to 10531115212055 its reverse (55021251113501), we get a palindrome (65552366325556).
The spelling of 10531115212055 in words is "ten trillion, five hundred thirty-one billion, one hundred fifteen million, two hundred twelve thousand, fifty-five".
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