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105315433 is a prime number
BaseRepresentation
bin1100100011011…
…11110001101001
321100011120121121
412101233301221
5203430043213
614241135241
72416111036
oct621576151
9240146547
10105315433
11544a2053
122b32a521
1318a85032
14ddb638d
1593a488d
hex646fc69

105315433 has 2 divisors, whose sum is σ = 105315434. Its totient is φ = 105315432.

The previous prime is 105315409. The next prime is 105315437. The reversal of 105315433 is 334513501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60652944 + 44662489 = 7788^2 + 6683^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-105315433 is a prime.

It is a super-2 number, since 2×1053154332 = 22182680855954978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105315398 and 105315407.

It is not a weakly prime, because it can be changed into another prime (105315437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52657716 + 52657717.

It is an arithmetic number, because the mean of its divisors is an integer number (52657717).

Almost surely, 2105315433 is an apocalyptic number.

It is an amenable number.

105315433 is a deficient number, since it is larger than the sum of its proper divisors (1).

105315433 is an equidigital number, since it uses as much as digits as its factorization.

105315433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 105315433 is about 10262.3307781420. The cubic root of 105315433 is about 472.2413436461.

Adding to 105315433 its reverse (334513501), we get a palindrome (439828934).

The spelling of 105315433 in words is "one hundred five million, three hundred fifteen thousand, four hundred thirty-three".