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10532556799993 is a prime number
BaseRepresentation
bin1001100101000100110101…
…0011100111111111111001
31101021220100222210202200001
42121101031103213333321
52340031134020044433
634222331221313001
72134644401430124
oct231211523477771
941256328722601
1010532556799993
1133a0917804198
121221343b65761
135b52a6297097
14285ac81953bb
15133e98d9a57d
hex9944d4e7ff9

10532556799993 has 2 divisors, whose sum is σ = 10532556799994. Its totient is φ = 10532556799992.

The previous prime is 10532556799991. The next prime is 10532556800023. The reversal of 10532556799993 is 39999765523501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10393060525929 + 139496274064 = 3223827^2 + 373492^2 .

It is a cyclic number.

It is not a de Polignac number, because 10532556799993 - 21 = 10532556799991 is a prime.

It is a super-2 number, since 2×105325567999932 (a number of 27 digits) contains 22 as substring.

Together with 10532556799991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (10532556799991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5266278399996 + 5266278399997.

It is an arithmetic number, because the mean of its divisors is an integer number (5266278399997).

Almost surely, 210532556799993 is an apocalyptic number.

It is an amenable number.

10532556799993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10532556799993 is an equidigital number, since it uses as much as digits as its factorization.

10532556799993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 620014500, while the sum is 73.

The spelling of 10532556799993 in words is "ten trillion, five hundred thirty-two billion, five hundred fifty-six million, seven hundred ninety-nine thousand, nine hundred ninety-three".