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1053331453463 is a prime number
BaseRepresentation
bin11110101001111110111…
…00100111011000010111
310201200211110221222010012
433110333130213120113
5114224210323002323
62123521020350435
7136046351425052
oct17247734473027
93650743858105
101053331453463
11376796166273
121501866a541b
13784372b12b3
1438da53bda99
151c5ed823678
hexf53f727617

1053331453463 has 2 divisors, whose sum is σ = 1053331453464. Its totient is φ = 1053331453462.

The previous prime is 1053331453429. The next prime is 1053331453477. The reversal of 1053331453463 is 3643541333501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1053331453463 - 220 = 1053330404887 is a prime.

It is a super-2 number, since 2×10533314534632 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1053331453463.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1053331453483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526665726731 + 526665726732.

It is an arithmetic number, because the mean of its divisors is an integer number (526665726732).

Almost surely, 21053331453463 is an apocalyptic number.

1053331453463 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053331453463 is an equidigital number, since it uses as much as digits as its factorization.

1053331453463 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 583200, while the sum is 41.

Adding to 1053331453463 its reverse (3643541333501), we get a palindrome (4696872786964).

The spelling of 1053331453463 in words is "one trillion, fifty-three billion, three hundred thirty-one million, four hundred fifty-three thousand, four hundred sixty-three".