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105340032137 is a prime number
BaseRepresentation
bin110001000011011000…
…0010101010010001001
3101001220022212002012202
41202012300111102021
53211214022012022
6120220442245545
710416265333214
oct1420660252211
9331808762182
10105340032137
114074677a2aa
12184ba1b68b5
139c19c44482
14515435677b
152b17e5b592
hex1886c15489

105340032137 has 2 divisors, whose sum is σ = 105340032138. Its totient is φ = 105340032136.

The previous prime is 105340032097. The next prime is 105340032139. The reversal of 105340032137 is 731230043501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84225326656 + 21114705481 = 290216^2 + 145309^2 .

It is a cyclic number.

It is not a de Polignac number, because 105340032137 - 26 = 105340032073 is a prime.

It is a super-2 number, since 2×1053400321372 (a number of 23 digits) contains 22 as substring.

Together with 105340032139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (105340032139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52670016068 + 52670016069.

It is an arithmetic number, because the mean of its divisors is an integer number (52670016069).

Almost surely, 2105340032137 is an apocalyptic number.

It is an amenable number.

105340032137 is a deficient number, since it is larger than the sum of its proper divisors (1).

105340032137 is an equidigital number, since it uses as much as digits as its factorization.

105340032137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 29.

Adding to 105340032137 its reverse (731230043501), we get a palindrome (836570075638).

The spelling of 105340032137 in words is "one hundred five billion, three hundred forty million, thirty-two thousand, one hundred thirty-seven".