Base | Representation |
---|---|
bin | 110001000011100000… |
… | …0000010101110001101 |
3 | 101001220121121022102111 |
4 | 1202013000002232031 |
5 | 3211221100303123 |
6 | 120221110424021 |
7 | 10416345334645 |
oct | 1420700025615 |
9 | 331817538374 |
10 | 105344150413 |
11 | 40749032437 |
12 | 184bb662011 |
13 | 9c1aa56b18 |
14 | 5154b09525 |
15 | 2b184c190d |
hex | 1887002b8d |
105344150413 has 2 divisors, whose sum is σ = 105344150414. Its totient is φ = 105344150412.
The previous prime is 105344150287. The next prime is 105344150503. The reversal of 105344150413 is 314051443501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77038443364 + 28305707049 = 277558^2 + 168243^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-105344150413 is a prime.
It is a super-2 number, since 2×1053441504132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105344130413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52672075206 + 52672075207.
It is an arithmetic number, because the mean of its divisors is an integer number (52672075207).
Almost surely, 2105344150413 is an apocalyptic number.
It is an amenable number.
105344150413 is a deficient number, since it is larger than the sum of its proper divisors (1).
105344150413 is an equidigital number, since it uses as much as digits as its factorization.
105344150413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 105344150413 its reverse (314051443501), we get a palindrome (419395593914).
The spelling of 105344150413 in words is "one hundred five billion, three hundred forty-four million, one hundred fifty thousand, four hundred thirteen".
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